Find the equation of line passing through points A (1, 3) and B (3, 7).
Accepted Solution
A:
Solution:To find the equation of line passing through points A (1, 3) and B (3, 7).we know that, to derive the equation of a line we first need to calculate the slope of the line. Slope m of a line at points [tex] (x_{1} ,y_{1}) [/tex] and [tex] (x_{2}, y_{2}) [/tex] is given by - [tex] m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} [/tex].Slope of the line at point A(1,3) and B(3,7) [tex] m=\frac{7-3}{3-1} [/tex]. [tex] m=\frac{4}{2} [/tex]. [tex] m=2 [/tex].Equation of a line using a point and a slope , [tex] y-y_{1}= m(x-x_1) [/tex] [tex] y-3= 2(x-1) [/tex] [tex] y-3= 2x-2 [/tex] [tex] y= 2x-2+3 [/tex] [tex] y= 2x+1 [/tex]The equation of line passing through points A (1, 3) and B (3, 7) : [tex] y= 2x+1 [/tex]